Half the perimeter of a rectangle …
Half the perimeter of a rectangle garden. whose lenght is 4 m more than it's width, is 36 m. Find the dimension of the garden
Posted by _Jass_ Mahey_ 8 months ago
- 2 answers
Given : Half the perimeter of a garden whose length is 4 m more than its width is 36 m. To do: We have to find the dimensions of the garden. Solution : Perimeter of a rectangle of length l and breadth b=2(l+b). Let the length of the rectangle be l and the width of the rectangle be b. Therefore, Half the perimeter of rectangle = 2 (l + b) 2 Half the perimeter of rectangle =l+b. Given that half the perimeter of the rectangular garden =36 m. l+b=36 m......(i) It is given that, length of the rectangular garden is 4 m more than its width. This implies, l=b+4.......(ii) Substituting (ii) in (i), we get, b+4+b=36 2b=36−4 2b=32 b= 32/2 b=16 m Substitute b=16 in (ii) l=16+4 l=20 m Therefore, the length of the rectangular garden is 20 m and the width of the rectangular garden is 16 m.
Let length be l and breadth be b of rectangular garden. l= b+4. (l+b)/2 = 36 . l+b= 72. b+4 + b = 72. 2b+4= 72. 2b= 68. b= 34 m. l=b+4 = 34+4= 38 m.
Accord of circle of radius 10 cm subtends a right angle at the centre find the area of the corresponding minor segment and major sector
Posted by Varsha Verma 17 hours ago
- 0 answers