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16x² - 16x - 21

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16x² - 16x - 21
  • 1 answers

Bhakti Parmar 2 months, 1 week ago

Solution  Verified by Toppr Given, f(x)=16x2−16x+28 f(x)=16x2−16x+4+24 ∴f(x)=(4x−2)2+24 we have,  (4x−2)2≥0 for all x∈R ⇒(4x−2)2+24≥0+24 for all x∈R ∴f(x)≥24 for all x∈R ∴x=24 is the minimum value. The function doesn't attain the maximum value at any point in its domain.
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