In given fig. O is the …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Lakshay Kumar 1 week, 2 days ago
- 0 answers
Posted by Parinith Gowda Ms 4 months ago
- 1 answers
Posted by Parinith Gowda Ms 4 months ago
- 0 answers
Posted by Kanika . 2 months ago
- 1 answers
Posted by Vanshika Bhatnagar 3 months, 4 weeks ago
- 2 answers
Posted by Hari Anand 2 weeks, 2 days ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Preeti Dabral 1 year, 8 months ago
As per given condition
Area of sector OAPB = {tex}\frac { 5 } { 36 }{/tex}times the area of circle
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { \theta } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\therefore \quad \pi r ^ { 2 } \times \frac { x } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }{/tex}
{tex}\frac { x } { 360 } = \frac { 5 } { 36 }{/tex} or,
{tex}\begin{array}{l}36\mathrm x=360\;\times5\end{array}{/tex}
{tex}\\\mathrm x=\frac{360\;\times5}{36}{/tex}
{tex}\\\mathrm x=\;10\;\times5{/tex}
{tex}\\\mathrm x\;=\;50{/tex}
0Thank You