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In given fig. O is the centre of a circle, If the area of the sector OAPB is 5/36 times the area of the circle then find the value of x.

Posted by Srusthi Sb 2 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 2 years, 1 month ago

As per given condition
Area of sector OAPB = $\frac { 5 } { 36 }$ times the area of circle
$\therefore \quad \pi r ^ { 2 } \times \frac { \theta } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }$
$\therefore \quad \pi r ^ { 2 } \times \frac { x } { 360 } = \frac { 5 } { 36 } \pi r ^ { 2 }$
$\frac { x } { 360 } = \frac { 5 } { 36 }$ or,
^{$\begin{array}{l}36\mathrm x=360\;\times5\end{array}$

$\\\mathrm x=\frac{360\;\times5}{36}$

$\\\mathrm x=\;10\;\times5$

$\\\mathrm x\;=\;50$}

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