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Shantanu decided to collect money for …

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Shantanu decided to collect money for buying motorcycle whose cost is ₹ 200,000. The initial amount in his Bank account is ₹ 50,000. On the basis of past drives, it is determined that after t months the beginning of the drive, the rate dx/dt at which money is arranged for his motorcycle is proportional to the difference between the desired goal of ₹ 200,000 and the total amount x in the Bank account at that time. After one month, a total of ₹ 100,000 is in the Bank account. Now answer the following questions using differential equation method: What is the differential equation created? What is the fund accumulated after 3 months? ₹ 1,50,000 ₹ 1,25,000 ₹ 1,55,555 ₹ 1,40,000 What is the fund accumulated after 5 months? ₹ 1,60,000 ₹ 1,35,000 ₹ 1,55,777 ₹ 1,80,246 What is the fund accumulated after t months? 2,00,000-150,000 2,00,000-150,000 2,00,000-100,000 2,00,000-125,000 What is the value of  in the equation: x = 200,000 - 150,000 e-k?
  • 1 answers

Preeti Dabral 2 years ago

  1. (a) {tex}\frac{dx}{dt}{/tex} = k( 200,000 - x)
  2. (c) ₹ 1,55,555
  3. (d) ₹ 180,246
  4. (a) 200,000 - 150,000{tex}\left(\frac23\right)^{\mathrm t}{/tex}
  5. (b) {tex}\frac23{/tex}
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