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A body dropped from top of …

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A body dropped from top of tower fall through 40m during the last two seconds of its fall. The height of tower is( g= 10 m/s^2

    • Posted by Miss Akanksha 1 year, 5 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Shanika Sharma 1 year, 4 months ago

    Let us suppose that during travelling 40 m in last 2 sec its initial velocity was u. Then, ut+1/2 gt² =40 =2u-19.6=40 u=29.8 m/sec Now considering from top to this position, u=0and v=29.8m/s Then by, v²−u²=2gh we get, 29.8²-0²=2×9.8×h h=45.3m So, total height of tower =45.3+40=85.30 m

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    Sanjay Gangwar 1 year, 5 months ago

    No

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    Aryan Singh 1 year, 5 months ago

    Sol or ans.

    5Thank You

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