A real estate company is going …
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Preeti Dabral 1 year, 5 months ago
Now, C{x) = 160 - 0.08x
For maxima/minima, put C'(x) = 0
{tex}\Rightarrow{/tex} 160 = 0.08x
{tex}\Rightarrow{/tex} x = 2000
Now, we have C(0) = 5000000
C(2000) = 5160000 and C(4500) = 4910000
{tex}\therefore{/tex} Maximum value of C(x) would be ₹5160000
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