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Find the area of quadrilateral ABCD …

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Find the area of quadrilateral ABCD whose vertices are A(1,1), B(7,-3), C(12,2) and D(7,21).

Posted by Reema Gupta 2 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Faisal Khan 2 years, 1 month ago

The coordinates of A,B,C & D are A(1,1),B(7,3),C(12,2),D(7,21). Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD Area of triangle = 2 1 ∣[x 1 (y 2 −y 3 )+x 2 (y 3 −y 1 )+x 3 (y 1 −y 2 )]∣ Area of triangle ABC = 2 1 ∣[1(3−2)+7(2−1)+12(1−3)]∣ = 2 1 ∣[1+7−24]∣ = 2 1 (16)=8 sq. units Area of triangle ACD = 2 1 ∣[1(2−21)+12(21−1)+7(1−2)]∣ = 2 1 ∣[−19+240−7]∣ = 2 1 (214)=107 sq. units Hence, area of quadrilateral ABCD = 107+8=115 sq. units

Bhavishay Chahar 2 years, 1 month ago

Rtfho

ANSWER

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