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Find the area of quadrilateral ABCD …

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Find the area of quadrilateral ABCD whose vertices are A(1,1), B(7,-3), C(12,2) and D(7,21).
  • 2 answers

Faisal Khan 2 months ago

The coordinates of A,B,C & D are A(1,1),B(7,3),C(12,2),D(7,21). Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD Area of triangle = 2 1 ​ ∣[x 1 ​ (y 2 ​ −y 3 ​ )+x 2 ​ (y 3 ​ −y 1 ​ )+x 3 ​ (y 1 ​ −y 2 ​ )]∣ Area of triangle ABC = 2 1 ​ ∣[1(3−2)+7(2−1)+12(1−3)]∣ = 2 1 ​ ∣[1+7−24]∣ = 2 1 ​ (16)=8 sq. units Area of triangle ACD = 2 1 ​ ∣[1(2−21)+12(21−1)+7(1−2)]∣ = 2 1 ​ ∣[−19+240−7]∣ = 2 1 ​ (214)=107 sq. units Hence, area of quadrilateral ABCD = 107+8=115 sq. units

Bhavishay Chahar 2 months ago

Rtfho
http://mycbseguide.com/examin8/

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