Shantanu decided to collect money for buying motorcycle whose cost is ₹ 200,000. The initial amount in his Bank account is ₹ 50,000. On the basis of past drives, it is determined that after t months the beginning of the drive, the rate dx/dt at which money is arranged for his motorcycle is proportional to the difference between the desired goal of ₹ 200,000 and the total amount x in the Bank account at that time. After one month, a total of ₹ 100,000 is in the Bank account. Now answer the following questions using differential equation method: What is the differential equation created? What is the fund accumulated after 3 months? ₹ 1,50,000 ₹ 1,25,000 ₹ 1,55,555 ₹ 1,40,000 What is the fund accumulated after 5 months? ₹ 1,60,000 ₹ 1,35,000 ₹ 1,55,777 ₹ 1,80,246 What is the fund accumulated after t months? 2,00,000-150,000 2,00,000-150,000 2,00,000-100,000 2,00,000-125,000 What is the value of in the equation: x = 200,000 - 150,000 e-k?
Posted by Sweety Rani 1 week, 6 days ago
- 1 answers
If the linear x-2/-3 =y-2/2k=z-3/2 and x-1/3k=y-1/1=z-6/-3 are perpendicular to each other then find the values of k?
Posted by M Keerthana Angel 1 week, 1 day ago
- 0 answers
Three friends Ravi, Raju and Rohit were buying and selling stationery items in a market. The price of per dozen of Pen, notebooks and toys are Rupees x, y and z respectively. Ravi purchases 4 dozen of notebooks and sells 2 dozen pens and 5 dozen toys. Raju purchases 2 dozen toys and sells 3 dozen pens and 1 dozen of notebooks. Rohit purchases one dozen of pens and sells 3 dozen notebooks and one dozen toys. In the process, Ravi, Raju and Rohit earn 1500, 100 and 400 respectively.
Posted by Aksha . S 1 week, 6 days ago
- 1 answers
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