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The area of circular wing 1 cm^2 carrying a current of 10A is passing through it, if the magnetic field intensities 0.1T is applied perpendicular to plane of ring.

Posted by Priyanshu Yadav 1 year, 8 months ago

CBSE > Class 12 > Physics

2 answers

Adithya Dev 1 year, 7 months ago

Torque τ = mB sin 90° = IAB × 1 = 10A × 10^-4 m^2 × 0.1 T = 10^-4 Nm. // Potential energy U = - mB cos 90° = 0//

★ 1 year, 8 months ago

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