No products in the cart.

$$\rm \displaystyle \int_{0}^{\dfrac{\pi}{2}} \dfrac{cos^2x dx}{cos^2x+4sin^2x}$$

CBSE, JEE, NEET, NDA

CBSE, JEE, NEET, NDA

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

$$\rm \displaystyle \int_{0}^{\dfrac{\pi}{2}} \dfrac{cos^2x dx}{cos^2x+4sin^2x}$$
  • 1 answers

Hitkar Miglani 2 months ago

Ans = π / 6
http://mycbseguide.com/examin8/

Related Questions

Integration of dx/1+cos²
  • 1 answers
Domain of sin root of x-1
  • 0 answers
Integ. Tan squad X
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Question Paper Creator

  • Create papers in minutes
  • Print with your name & Logo
  • Download as PDF
  • 5 Lakhs+ Questions
  • Solutions Included
  • Based on CBSE Syllabus
  • Best fit for Schools & Tutors

Test Generator

Test Generator

Create papers at ₹10/- per paper

Download myCBSEguide App