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$$\rm \displaystyle \int \dfrac{dx}{x\sqrt{x^4-1}}$$

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$$\rm \displaystyle \int \dfrac{dx}{x\sqrt{x^4-1}}$$
  • 2 answers

Gautam Aggarwal 2 years, 10 months ago

Let x⁴= t

Gautam Aggarwal 2 years, 10 months ago

Multiply numerator and denominator by x³ and then let x⁴-1=t and differentiate both side w.r.t x and then proceed.
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