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Find the remainder when x 3−ax2+6x−a …

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Find the remainder when x 3−ax2+6x−a is divided by x-a.

Posted by Satyajit Ray 3 years, 11 months ago

CBSE > Class 09 > Mathematics

2 answers

Prince Goyal 3 years, 11 months ago

g(x)=0 x-a=0 x=a Put the value of x in p(x) p(a)=3-ax2+6x-a 3-a×2+6×x=a 3-2a+6x=a ...3-2a+6a=a 3=2a-6a+a 3=-3a a=3÷-3 a=-3÷3 . a=-1

Sanket .........✨ 3 years, 11 months ago

x - a = 0 , x = a Then put the value of x in p(x)

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This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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