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Find the remainder when x 3−ax2+6x−a …

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Find the remainder when x 3−ax2+6x−a is divided by x-a.
  • 2 answers

Prince Goyal 1 week, 5 days ago

g(x)=0 x-a=0 x=a Put the value of x in p(x) p(a)=3-ax2+6x-a 3-a×2+6×x=a 3-2a+6x=a ...3-2a+6a=a 3=2a-6a+a 3=-3a a=3÷-3 a=-3÷3 . a=-1

—͟͞͞★Sanket 💫 1 week, 6 days ago

x - a = 0 , x = a Then put the value of x in p(x)
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