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. Show that p(x) = x3 …

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. Show that p(x) = x3 – 3x2 + 2x – 6 has only one real zero. 3.

Posted by Prince Kumar 4 years, 1 month ago

Rita Sarda 4 years, 1 month ago

Let the number of persons be x. Then, x−496−x96=4⇔x−41−x1=964⇔x(x−4)x−(x−4)=241 ⇔x2−4x−96=0⇔(x−12)(x+8)=0⇔x=12 So, required number =x−4=8.

Sancha Maya 4 years, 1 month ago

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