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. Show that p(x) = x3 …

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. Show that p(x) = x3 – 3x2 + 2x – 6 has only one real zero. 3.
  • 2 answers

Rita Sarda 1 month, 3 weeks ago

Let the number of persons be x. Then, x−496​−x96​=4⇔x−41​−x1​=964​⇔x(x−4)x−(x−4)​=241​                                ⇔x2−4x−96=0⇔(x−12)(x+8)=0⇔x=12 So, required number =x−4=8.

Sancha Maya 1 month, 3 weeks ago

어험가쩌쏘 떷텊초 추흐ㅛ허모
http://mycbseguide.com/examin8/

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