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The principal value of the expression cos^-1(cos (- 680°))

Posted by Megana Prabha 3 years ago

CBSE > Class 12 > Mathematics

1 answers

Kunishka Yadav 3 years ago

2π/9 will be the answer. Solution: cos^-1 ( cos (-680°)) =cos^-1 (cos (720°- 40°)) =cos^-1 (cos (40°)) = 40° = 2π/9

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