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log^cosec x=y

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log^cosec x=y
  • 3 answers

Bhumika Agrawal 3 years, 4 months ago

dy/dx = 1/cosec x * d(cosec x )/dx dy/dx = 1/cosec x * (-cosec x. cot x) dy/dx = -cot x

Bhumika Agrawal 3 years, 4 months ago

Right question is log (cosec x)= y

Bhumika Agrawal 3 years, 4 months ago

This question is wrong
http://mycbseguide.com/examin8/

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