Let R be the set of …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Arnab H. 4 years, 5 months ago
- 2 answers
Account Deleted 4 years, 5 months ago
Here I will tell you how to find F0g & hope you will find the remaining.
f0g is pronounced as f of g(x)
f0g = f{g(x)} = f {{tex}x \over x^2 +1{/tex}}
We have put the value of g(x) given in question.
Now let us assume that {tex}{x \over x^2 +1} = y{/tex}
Therefore, f {{tex}x \over x^2 +1{/tex}} = f{y}
as f{x} = 3x+2
f{y} = 3y +2
Therefore
f{{tex}{x \over x^2 +1}{/tex}} = 3 * {tex}{x \over x^2 +1}{/tex} + 2
=> f0g = {tex}{3x \over x^2 +1} +2 {/tex}
On Solving
f0g = {tex}{3x + 2x^2 +2\over x^2 +1}{/tex}
Answer.
Related Questions
Posted by Sanjna Gupta 1 year, 2 months ago
- 4 answers
Posted by Sneha Pandey 1 year, 3 months ago
- 0 answers
Posted by Ananya Singh 1 year, 3 months ago
- 0 answers
Posted by Xxxxxx Xx 1 year, 2 months ago
- 3 answers
Posted by Xxxxxx Xx 1 year, 2 months ago
- 0 answers
Posted by Charu Baid 1 year, 2 months ago
- 0 answers
Posted by Karan Kumar Mohanta 1 year, 2 months ago
- 0 answers
Posted by Sanjay Kumar 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Arnab H. 4 years, 5 months ago
1Thank You