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Find second order derivative sin(logx)

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Find second order derivative sin(logx)

Posted by Vishu Pundir 3 years, 10 months ago

CBSE > Class 12 > Mathematics

1 answers

Kapil Adhikari 3 years, 10 months ago

Y=sin(logx)

dy/dx=cos(logx) .1/x)

Now,by quotient rule

d²y/dx²=[x(-sin(logx).1/x)- cos(logx).1]/x²

d²y/dx²=[-sin(logx)-cos(logx)] /x²

2Thank You

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