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Find second order derivative sin(logx)

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Find second order derivative sin(logx)

    • Posted by Vishu Pundir 4 years, 8 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Kapil Adhikari 4 years, 8 months ago

    Y=sin(logx)

    dy/dx=cos(logx) .1/x)

    Now,by quotient rule

    d²y/dx²=[x(-sin(logx).1/x)- cos(logx).1]/x²

    d²y/dx²=[-sin(logx)-cos(logx)] /x²

    2Thank You

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