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Solve the equation dy/dx =ycotx , …

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Solve the equation dy/dx =ycotx , given X=π/2, y=1

Posted by Aarti Rana 3 years, 7 months ago

CBSE > Class 12 > Mathematics

1 answers

Rajnish Yadav 3 years, 7 months ago

dy/dx=ycotx (separate variable both side) dy/y=cotx dx (Integration both side) logy=log(sinx)+c logy-log(sinx)=logc (loga-logb=loga/b) logy/sinx=logc y/sinx=c y=sinx(c)

8Thank You

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