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Inverse cos x upon 1 minus …

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Inverse cos x upon 1 minus sin x in simplest form
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Shubham Hatwal 3 years, 7 months ago

=Cosx÷[1-sinx] =Sin(π/2-x)÷[1-cos(π/2-x] =2sin(π/4-x/2)cos(π/4-x/2)÷2sin^2(π/4-x/2) =cot(π/4-x/2) {Formula used in third step is (sin2x=2 sinxcosx ) and (1-cos2x= 2sin^2(x) ) }
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