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y-xdy/DX=a(y^2+x^2dy/DX)

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y-xdy/DX=a(y^2+x^2dy/DX)
  • 2 answers

Bhupesh Rao 3 years, 9 months ago

y-ay^2=ax^2dy/dx+xdy/dx Taking dy/dx common in rhs y-ay^2=(ax^2+x)dy/dx dy/dx=y-ay^2/(ax^2+x)

Bhupesh Rao 3 years, 9 months ago

Taking dy/dx same side
http://mycbseguide.com/examin8/

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