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x=(t+1/t)^a y=a^(t+1/t) find dy/dx

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x=(t+1/t)^a y=a^(t+1/t) find dy/dx

Posted by Simar Kaur 3 years, 9 months ago

CBSE > Class 12 > Mathematics

2 answers

Twinkle . 3 years, 9 months ago

a^(1/t).t^(a-1).log a.(t+1)^(1-a)

Gurharman Kaur 3 years, 9 months ago

dy/dx=(-a^t+1/t.loga)/a.(t+1/t)^a-1.1/t^2

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