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P(A)=0.8, P(B)=0.5 and P(B/A)=0.4 . Find …

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P(A)=0.8, P(B)=0.5 and P(B/A)=0.4 . Find ?(? ∩ ?).

Posted by Amar Sankar Mahato 3 years, 9 months ago

CBSE > Class 12 > Mathematics

5 answers

Yash Nagwal 3 years, 9 months ago

5/4

Twinkle . 3 years, 9 months ago

P(B/A) = 0.4 P(B∩A)/ P(B) = 0.4 P( B ∩ A) / 0.5 = 0.4 P( B ∩ A) = 0.4×0.5 P( A ∩ B) = 0.20

Ashish Tanwar 3 years, 9 months ago

??

Rajaneha Rajasekar 3 years, 9 months ago

P(B/A)= 0.4= p(A intersection B) /p(A) . Then p( A intersection B) = p(B/A) × P(A) .that is p(A intersection B) = 0.4×0.8= 0.32

Parth Pathak 3 years, 9 months ago

P(B/A) = 0.4 P(B intersection A)/ P(B) = 0.4 P( B intersection A) / 0.5 = 0.4 P( B intersection A) = 0.4*0.5 P( A intersection B) = 0.20

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