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Solve the differential equation Log(dy/dx)=ax+by.

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Solve the differential equation Log(dy/dx)=ax+by.
  • 1 answers

Vaibhav Yadav 3 years, 10 months ago

Log(dy/dx)=ax+by => dy/dx=e^{ax+by} => dy/dx=e^(ax).e^(by) => dy/e^(by)=e^(ax)dx =>e^(-by)dy=e^(ax)dx Integrating both sides, -e^(-by)/b=e^(ax)/a + c
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