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Find the equatio of the tangent …

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Find the equatio of the tangent to the curve y=x-7/(x-2)(x-3) at th point where it cuts xaxis

Posted by Satinder Kaur Dhillon 3 years, 5 months ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 3 years, 5 months ago

We have given
y = x-7/(x-2)(x-3)......(i)
Let (i) cuts the x-axis at (x, 0)
then x-7/(x-2)(x-3) =0 =>x=7
the required point is (7, 0).
Differentiating equation (i) w.r.t. x, we get

0Thank You

ANSWER

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