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If x=a(CosQ+QsinQ),Y=a(sinQ-QcosQ) ,then find dy/dx, at …

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If x=a(CosQ+QsinQ),Y=a(sinQ-QcosQ) ,then find dy/dx, at Q=pie/4
  • 3 answers

Tanay Bhushan 3 years, 10 months ago

at π/4 dy/dx=1

Tanay Bhushan 3 years, 10 months ago

dx/dQ=-asinQ+aQcosQ+asinQ dx/dQ=aQcosQ -(1) dy/dQ= acosQ+aQsinQ-acosQ dy/dQ= aQsinQ -(2) From eq first and second we have dividing eq (2) by eq(1) dy/dx=(dy/dq) /(dq/dx) So dy/dx=(aQsinQ) /(aQcosQ) dy/dx=tanQ

Tuleshwar Sahu 3 years, 10 months ago

2+45
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