Write 1+cosx= 2 cos^2(x/2) Then (x+sinx)/(1+cosx )= (1/2)xsec^2(x/2) (apply integration by parts to evaluate) + sinx/2cos^2(x/2)(Apply sinx =2sin(x/2)cos(x/2) to evaluate)

1Thank You

Mahi Kumari 3 years, 10 months ago

I think the question is reversed by mistake and it would be like "integration of function (1+cosx/ x+sinx) w.r.t x from limit 0 to π, so that we can able to substitute t = (x+sinx) and it's differential form would be (1+cosx). Check please.

2Thank You

Prakhar Chouksey 3 years, 10 months ago

Substitute 1+cosx=t

5Thank You

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