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- if the system of linear equations →x + ky +3z=0,3x+ ky -2z=0, 2x + ky -3z = 0 has a non-zero solution (x,y,z) then xz/y² is equal to ????the question from jee 2018 of defferetail equation .

    • Posted by Shraddha ✨✰✰ 3 years, 10 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Shivansh Kaushik 3 years, 10 months ago

    x+ky+3z=0 ..(1) 3x+ky−2z=0 ..(2) 2x+4y−3z=0 ..(3) For non-zero solutions to exist: Find the value of k by determinant method of linear equations. Solving the above determinant equation, we get −3k+8−k(−9+4)+3(12−2k)=0 ⇒k=11 Solving equations (1), (2) and (3), we get 2x=5z & 3x=−(k+4)y ⇒2x=5z&x=−5y Now,  xz/y^2=(x​)(2x/5)/[-x/5]^2=10

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