Integrate the function (x³-1)⅓.x⁵
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Posted by Prince Goyal 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
given function is ∫(x³ - )^⅓ x^5.dx
let (x³ - 1) = t , and x³ = (1 + t)
⇒3x² = dt/dx
⇒dx = dt/3x²
So, ∫(x³ - 1)^⅓ x^5 * dt/3x²
⇒1/3 ∫t^⅓ (1 + t) *dt
⇒1/3 ∫(t^⅓ + t^{4/3}).dt
⇒1/3 ∫t^{1/3}.dt + 1/3∫t^{4/3}.dt
⇒1/3 + 1/3
+ c
put the value of t in the above function,
⇒.
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Sahil Kumar 4 years, 9 months ago
1Thank You