Cosa/1-sina+sina/1-cosa+1=sinacosa/(1-sina)(1-cosa)

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Cosa/1-sina+sina/1-cosa+1=sinacosa/(1-sina)(1-cosa)

Posted by Tamil Selvi 7 years, 8 months ago

CBSE > Class 12 > Mathematics

1 answers

Rajeev Malhotra 7 years, 8 months ago

$cosA/1-Sin A +Sin A/1- Cos A +1$

$Cos A(1-Cos A)+Sin A(1-Sin A)+(1-Sin A)(1-Cos A)/(1-Sin A) (1-Cos A)$

$Cos A- Cos^2A+Sin A- Sin^2A+1-SinA- Cos A+Sin ACos A/(1-Sin A)(1-CosA)$

$1-(Cos^2A+Sin ^2A)+SinA CosA/ (1-SinA)(1-CosA)$

$1-1+SinA Cos A/ (1-Sin A)(1-CosA)$

$Sin A CosA/ (1-Sin A)(1-CosA)$

L.H.S = R.H.S

0Thank You

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