Cosa/1-sina+sina/1-cosa+1=sinacosa/(1-sina)(1-cosa)
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Posted by Tamil Selvi 8 years, 1 month ago
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Rajeev Malhotra 8 years, 1 month ago
{tex}cosA/1-Sin A +Sin A/1- Cos A +1{/tex}
{tex}Cos A(1-Cos A)+Sin A(1-Sin A)+(1-Sin A)(1-Cos A)/(1-Sin A) (1-Cos A){/tex}
{tex}Cos A- Cos^2A+Sin A- Sin^2A+1-SinA- Cos A+Sin ACos A/(1-Sin A)(1-CosA){/tex}
{tex}1-(Cos^2A+Sin ^2A)+SinA CosA/ (1-SinA)(1-CosA){/tex}
{tex}1-1+SinA Cos A/ (1-Sin A)(1-CosA){/tex}
{tex}Sin A CosA/ (1-Sin A)(1-CosA){/tex}
L.H.S = R.H.S
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