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Find the value of (1-w+w²)⁶+ (1-w²+w)⁶

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Find the value of (1-w+w²)⁶+ (1-w²+w)⁶
  • 1 answers

Dev'S Educare 3 years, 11 months ago

Ans:-64

(-2w)^6  + (-2w2)^6

=64w^6  +  64 w^12

=64w^6(1+w^2)

=64(-w^3)

=-64

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