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EXERCISE 13.8 2nd problem

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EXERCISE 13.8 2nd problem
  • 1 answers

Pratyush Pradyun Subrata 3 years, 5 months ago

2. Find the amount of water displaced by a solid spherical ball of diameter (i) 28 cm (ii) 0.21 m (Assume π =22/7) Solution: (i) Diameter = 28 cm Radius, r = 28/2 cm = 14cm Volume of the solid spherical ball = (4/3) πr3 Volume of the ball = (4/3)×(22/7)×143 = 34496/3 Hence, volume of the ball is 34496/3 cm3 (ii) Diameter = 0.21 m Radius of the ball =0.21/2 m= 0.105 m Volume of the ball = (4/3 )πr3 Volume of the ball = (4/3)× (22/7)×0.1053 m3 Hence, volume of the ball = 0.004851 m3
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