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Differentiation of e^sinx

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Differentiation of e^sinx

    • Posted by Shivam Vishwakarma 4 years ago

    CBSE > Class 12 > Mathematics
    • 3 answers

    Chiranjeevi Kaushal 3 years, 11 months ago

    Given , The function y = e^x Differentiaing y wrt x by using chain rule , we get Dy/dx = d(e^sinx)/dx Dy/dx = e^sinx × d(sinx)/dx Dy/dx = e^sinx × cosx For easier calculation Remmember :- D(e^x)/dx = e^x D(sinx)/dx = cosx _____ Insta ID - its_sagar3111

    0Thank You

    Kunal Attri 4 years ago

    e^sinx.cosx

    0Thank You

    Akshay Viswanathan 4 years ago

    Let y= e^sinx Taking log on both sides ln(y) =sinx Differentiating on both sides we get, (1/y) (dy/dx) =cosx dy/dx = y cosx But y=e^sinx Therefore, answer is (e^sinx) cosx Hope it helped you!

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