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y=x^sinx+sin^-1✓x find derivative

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y=x^sinx+sin^-1✓x find derivative

Posted by Shivam Nosaliya 4 years, 1 month ago

CBSE > Class 12 > Mathematics

2 answers

Shraddha ✨✰✰ 4 years, 1 month ago

Sorry ans . adhura chhod diya. Then, dv/dx = 1/√1-(x)².d√x/dx , dv/dx =1/√1-x.1/2√x. , dv/dx = 1/2√x×√1-x. , dv/dx = 1/2√x(1-x). , dv/dx = 1/2√x-x² Then , dy/dx = du/dx + dv/dx , then dy/dx = x^sinx ×(sinx + x cosx .logx )/x + 1/2√x-x² , and first vale ans me jo dy/dx find kiya hai vo du/dx hai. Ok

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Shraddha ✨✰✰ 4 years, 1 month ago

dy/dx = du/dx. +. dv/dx then, first we find the du/dx y = x^sinx then , y = e^sinx.logx Differ. W.r.t. x dy/dx = d/dx (e^ sinx.logx) dy/dx =e^sinx.logx .d/ dx(sinx.logx) dy/dx = x^sinx [sinx .d/dx logx + logx.d/dx sinx ] dy/dx = x^sinx (sinx + x cosx.logx )/x then , we find dv/dx dv/dx = d(sin-¹√x)/dx dv/dx = 1/√(1

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