ABCD is a trapezium with AB …
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Gaurav Seth 3 years, 6 months ago
ABCD is a trapezium with AB || DC, E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB show that
<hr />Given trap. ABCD in which AB || DC and EF || AB.
To prove:
Const: Join A-C.
Proof: ∵ AB || DC and EF || AB
⇒ AB || EF || DC
Now, in ∆ADC, we have
[using Basic proportionality theorem]
Now, in ∆ABC, we have
...(ii)
Comparing (i) and (ii), we get
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