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The area of a triangle with …

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The area of a triangle with vertices(-3,0),(3,0)and(0,k) is 9 sq.units. find the value of k.

    • Posted by Aman Badhwar 5 years ago

    CBSE > Class 12 > Mathematics
    • 2 answers

    Shraddha ✨✰✰ 5 years ago

    Ans. → = 1/2( x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2) = 1/2 [ -3 ( 0 - k ) + 3 ( k - 0 ) + 0 ( 0 - 0 ) = 1/2 [-3(k) + 3k + 0 ] = 1/2 ( 3k + 3k ) .°. 3k = 9 (°.° ar.∆ABC = 9 unit² ) .°. k = 3 ans.

    0Thank You

    Krati Varshney 5 years ago

    Use the formula of area of triangle :- 1/2 (x1(y2-y3)+x2 (y3-y1)+x3 (y1-y2))=0 Put all the given values in this then u will get ur answer urself..??

    0Thank You

    ANSWER
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