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differentiation of log^2x+logx

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differentiation of log^2x+logx
  • 3 answers

Arjit Arjit 4 years, 1 month ago

2logx+logx 3logx Now dy/dx=d/dx (3logx) =3/x

Iqbal Singh 4 years, 2 months ago

ok thanks mera answer aa geya bro agin thanks????

Mr. Badmash 4 years, 2 months ago

Firstly write log^2x+logx.,,,,, As (logx)^2+logx and apply log property of power then solve it by itself....??? Agar fir bhi nhi bane to bta dena
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