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Solve : $$\lim_{x \to 1} \left(\dfrac{3x^2 …

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Solve :
$$\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1} \right)$$
  • 4 answers

Dεερακ Ȿιηɠꜧ 4 years, 5 months ago

$$\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1 } \right) = $$\left(\dfrac{16}{0} \right) = $$\left(\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \right) = I don't know what to do next ???

Dεερακ Ȿιηɠꜧ 4 years, 5 months ago

\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1 } \right)
= \left(\dfrac{16}{0} \right)
= \left(\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \right)
= I don't know what to do next ???

Anshu Kumar 4 years, 5 months ago

Done

Aseem Mahajan 4 years, 5 months ago

Coding challenge??????
http://mycbseguide.com/examin8/

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