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Solve : $$\lim_{x \to 1} \left(\dfrac{3x^2 …

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Solve :
$$\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1} \right)$$

Posted by ★ 3 years, 7 months ago

CBSE > Class 11 > Mathematics

4 answers

Dεερακ Ȿιηɠꜧ 3 years, 7 months ago

$$\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1 } \right) = $$\left(\dfrac{16}{0} \right) = $$\left(\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \right) = I don't know what to do next ???

0Thank You

Dεερακ Ȿιηɠꜧ 3 years, 7 months ago

\lim_{x \to 1} \left(\dfrac{3x^2 +2x + 1}{x^2 - 1 } \right)
= \left(\dfrac{16}{0} \right)
= \left(\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \right)
= I don't know what to do next ???

0Thank You

Anshu Kumar 3 years, 7 months ago

Done

0Thank You

★ 3 years, 7 months ago

Coding challenge??????

1Thank You

ANSWER

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CBSE > Class 11 > Mathematics