No products in the cart.

The position of a particle moving …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

The position of a particle moving along a straight line is given by .....x = 2 - 5t +6 t ^ 2 Find accl of particle at t = 2 sec ?
  • 1 answers

Aseem Mahajan 4 years, 2 months ago

a = $$\frac{d^2x}{dt^2}$$
a = $$\frac{d}{dt} 12t - 5$$
a = 12 m/s³ at every time means it >s constant
http://mycbseguide.com/examin8/

Related Questions

Project report
  • 0 answers
2d+2d =
  • 1 answers
√kq,qpower2 R2
  • 0 answers
Ch 1 question no. 14
  • 0 answers
1dyne convert to S.I unit
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App