# The position of a particle moving …

The position of a particle moving along a straight line is given by .....x = 2 - 5t +6 t ^ 2 Find accl of particle at t = 2 sec ?
a = $$\frac{d^2x}{dt^2}$$
a = $$\frac{d}{dt} 12t - 5$$
a = 12 m/s³ at every time means it >s constant

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