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The resistance R=v/I where V=(100+-5) and …

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The resistance R=v/I where V=(100+-5) and I=(10+-0.2)A. Find the percentage of error

    • Posted by Mycbse Guide 3 years, 7 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Mukul Tyagi 3 years, 7 months ago

    V=100+-5 & I= 10+-0.2A R=V/I (∆R/R)×100= (∆V/V)×100 + (∆I/I)×100 (∆R/R)×100= (5/100)×100+(0.2/10)×100 (∆R/R)×100= (1/20)×100+(1/50)×100 (∆R/R)×100= (5+2)% (∆R/R)×100= 7% Answer.....

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