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Y=x cos x. Find d^2y/dx^2

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Y=x cos x. Find d^2y/dx^2
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Harshita Bhambhani 4 years, 2 months ago

Y=x cosx dy/dx = cosx d/dx(x) +x d/dx(cosx) dy/dx = cosx + x(-sinx) dy/dx = cosx - xsinx d^2y/dx^2 = d/dx (cosx - xsinx) d^2y/dx^2 = d/dx(cosx) - d/dx(xsinx) d^2y/dx^2 = (-sinx) - {(sinx)+x(cosx)} d^2y/dx^2 = -sinx-sinx-xcosx =-(2sinx+xcosx)
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