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Consider the function f :[0,π/2] to …

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Consider the function f :[0,π/2] to R , given by f(x) = sinx and g:[0,π/2] to R given by g(x) = cosx . Show that f and g one-one but f+g is not one-one .

    • Posted by Priyanka Birat 4 years, 3 months ago

    CBSE > Class 12 > Mathematics
    • 2 answers

    Tannu Rao 4 years, 3 months ago

    U can draw graphs of cosx and sinx in interval [0,π/2]. From the graphs, we can infer that both the functions are one one. Or f'(x)=cosx and g'(x)=-sinx. Derrivatives of both the functions are only +ve and -ve respectively in the given interval. Hence both are one one. (f+g)(x)=sinx +cosx (f+g)'(x)=cosx-sinx which is both +ve as well as -ve in the given interval. Hence it is many one.

    0Thank You

    Priyanka Birat 4 years, 3 months ago

    Can anyone solve this question in good explanation .

    2Thank You

    ANSWER
    http://mycbseguide.com/examin8/

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