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Sinx+cosx/9+16sin2x

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Sinx+cosx/9+16sin2x

    • Posted by Bharat Bhushan 8 years, 1 month ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Khushbu Chouksey 8 years, 1 month ago

    =>Sinx + cosx/9+16-16+16sin2x Sinx + cosx/1]5-16(1-sin2x) Sinx + cosx/25-16(Sin²x+cos²x-2sinxcosx) Sinx + cosx/25-16(sinx-cosx)² ---(i) Let sinx-cosx = t -----(ii) On Differentiating (sinx + cosx)dx = dt ----(iii) Integrating equation (i) and Putting these values from (ii) and (iii) dt/25-16t² dt/(5)²-(4t)² Let 4t = u 4dt =du => 1/4[du/(5)²-(u)²] Now integrate this using identity integration dx/a²-x² = 1/2a[log((a+x)/(a-x))] +c Hope it helps!!

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