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Let f:R-R be defined by f(x)=x²+1 …

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Let f:R-R be defined by f(x)=x²+1 then pre-image of -3 is
  • 2 answers

Khushi....? ??‍? 4 years, 5 months ago

The answer is phi its value cannot be defined because root of -4 is imaginary....and function is not possible hence -3 has no pre image.... For more clear explanation.... f(x)=x^2+1... For pre image of -3 f(x)=-3...solving this we get root -4 which is not possible....

Ayush Vishwakarma?? 4 years, 5 months ago

10
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