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tan(sin‐¹ 3/5 + cot‐¹ 3/2)

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tan(sin‐¹ 3/5 + cot‐¹ 3/2)

    • Posted by ?????? ???? . 4 years, 5 months ago

    CBSE > Class 12 > Mathematics
    • 2 answers

    ? ? 4 years, 5 months ago

    It is so simple.... just change sin inverse3/5 to tan inverse 3/4 by triangle's method. Then convert cot inverse3/2 to tan inverse 2/3 and applt the formula for tan inverse 3/4 +tan inverse2/3. At last both tan and tan inverse will be cancel out and answer will be 17/6...

    2Thank You

    Jaspreet Singh 4 years, 5 months ago

    Let sin -¹ 3/5 =a Sin a = 3/5 Cos a = underroot 1- sin² a = 4/5 Let cot-¹ 3/2 =b Cot b =3/2 Sin b = 1/cosec b = 1/underroot 1+cot ²b = 2/underroot 13 So, A. T. Q, = 4/5 + 2 / underroot 13 = 4under.. 13 + 10 / 5 underroot 13 = ANSWER..................!!!!!!!!!!!!!!!!

    2Thank You

    ANSWER
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