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Equation of a circle is x^2+y^2-2x+4y=0. …

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Equation of a circle is x^2+y^2-2x+4y=0. Find equation of one of its diameter.

Posted by Ayushi Patel 4 years ago

CBSE > Class 12 > Applied Mathematics

5 answers

Lokendra Tomar 3 years, 5 months ago

Aap kha se ho

Ravindra Bijarniya 3 years, 5 months ago

Oo bhai kaha se laya hai

Satyam Mishra 3 years, 5 months ago

Wffnt qeeeey136677#^ vevvvvvw%,'%++!%_€£*^:@:#,$?*$^#)×₩×₹£÷€÷_$&;#;÷:"×€£》~■~{○{○[》~《○■○■▪︎<>《¤☆¡▪︎¿》¤♧¤◇•]~{\>|>|[~♤○》¤》¤

Yash Sharma 3 years, 5 months ago

??oo bhai kya hai ye

Dhruv Sarkar 3 years, 11 months ago

The equation can be written as (x-1)^2 + (y+2)^2 = 5. —(1). => center of the circle is at O(1,-2). Now solve for eq(1) and y=0 so that we get the point(s) of intersection of the circle with the x-axis.The points will be A(3,0) and B(-1,0). The equation of the line OA will then be (by using two point form), x-y-3=0, which is the equation of one of the diameters,

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Posted by Pranav Makkar 2 months, 3 weeks ago

CBSE > Class 12 > Applied Mathematics

1 answers

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.

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